Atomic Structure Problems 1

Atomic Structure Problems

Energy Ratio of Radiation

Problems in Atomic Structure:

What is the ratio between energy of two types of radiation whose wavelengths are 6000 Angstrom and 2000 Angstrom respectively?

Answer:

To find the ratio of the energy of two types of radiation based on their wavelengths, we use the following relationship between energy and wavelength:

E = hc / λ

Where:

  • E is the energy of the radiation,
  • h is Planck's constant (6.626 × 10-34 J·s),
  • c is the speed of light (3 × 108 m/s),
  • λ is the wavelength of the radiation.
Step 1: Define the wavelengths
  • For the first radiation, λ1 = 6000 Å = 6000 × 10-10 m = 6 × 10-7 m
  • For the second radiation, λ2 = 2000 Å = 2000 × 10-10 m = 2 × 10-7 m
Step 2: Energy ratio formula

The ratio of energy E1 (for λ1) to E2 (for λ2) is given by:

E₁ / E₂ = λ₂ / λ₁
Step 3: Therefore
E₁ / E₂ = (2 × 10-7) / (6 × 10-7) = 2 / 6 = 1 / 3
Neutron Ratio in Carbon Isotopes

2.What is the ratio between the number of neutrons present in carbon isotopes with mass numbers 12 and 14?

Step 1: Understanding Carbon Isotopes

Carbon-12 and Carbon-14 are isotopes of carbon. Isotopes have the same number of protons but different numbers of neutrons. .

Step 2: Number of Neutrons in Each Isotope
  • Carbon-12 (C-12): The mass number is 12. The number of neutrons is:
    Neutrons = Mass Number - Protons = 12 - 6 = 6 neutrons.
  • Carbon-14 (C-14): The mass number is 14. The number of neutrons is:
    Neutrons = Mass Number - Protons = 14 - 6 = 8 neutrons.
Step 3: Ratio of Neutrons

The ratio of neutrons in Carbon-12 to Carbon-14 is:

Neutrons in C-12 / Neutrons in C-14 = 6 / 8 = 3 / 4

Conclusion:

The ratio between the number of neutrons in Carbon-12 and Carbon-14 is 3:4.

Nitride Ion (N³⁻) - Protons, Electrons, and Neutrons

3.What are the number of protons, electrons, and neutrons present in a nitride ion (N³⁻)?

The following table shows the number of protons, electrons, and neutrons present in a nitride ion (N³⁻):

Particle Number in Nitride Ion (N³⁻)
Protons 7
Electrons 10
Neutrons 7

Explanation:

  • Protons: The atomic number of nitrogen is 7, so the number of protons is 7.
  • Electrons: The nitride ion (N³⁻) has gained 3 extra electrons, so it has 7 + 3 = 10 electrons.
  • Neutrons: The most common isotope of nitrogen has a mass number of 14. Neutrons are calculated as mass number - atomic number, so 14 - 7 = 7 neutrons.

Author

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